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Find mutual friends count from given relation ship array. Substantive Expertise

This is a good example of the “substantive expertise” aspect of data science. users = [     { "id": 0, "name": "Hero" },     { "id": 1, "name": "Dunn" },     { "id": 2, "name": "Sue" },     { "id": 3, "name": "Chi" },     { "id": 4, "name": "Thor" },     { "id": 5, "name": "Clive" },     { "id": 6, "name": "Hicks" },     { "id": 7, "name": "Devin" },     { "id": 8, "name": "Kate" },     { "id": 9, "name": "Klein" } ] friendship_pairs = [(0, 1), (0, 2), (1, 2), (1, 3), (2, 3), (3, 4),                     (4, 5), (5, 6), (5, 7), (6, 8), (7, 8), (8, 9)] # Initialize the dict with an empty list for each user id: friendships = {user["id"]: [] for user in users} # And ...